Hi,

Please consider applying.

Description: Use msleep() instead of schedule_timeout() to guarantee the task
delays as expected. The current code uses TASK_INTERRUPTIBLE, but does not check
for signals, so I believe the change to msleep() should be ok.

Signed-off-by: Nishanth Aravamudan <nacc@us.ibm.com>
Signed-off-by: Domen Puncer <domen@coderock.org>
---


 kj-domen/net/atm/resources.c |    4 ++--
 1 files changed, 2 insertions(+), 2 deletions(-)

diff -puN net/atm/resources.c~msleep-net_atm_resources net/atm/resources.c
--- kj/net/atm/resources.c~msleep-net_atm_resources	2005-01-23 00:24:19.000000000 +0100
+++ kj-domen/net/atm/resources.c	2005-01-23 00:24:19.000000000 +0100
@@ -16,6 +16,7 @@
 #include <linux/kernel.h> /* for barrier */
 #include <linux/module.h>
 #include <linux/bitops.h>
+#include <linux/delay.h>
 #include <net/sock.h>	 /* for struct sock */
 
 #include "common.h"
@@ -138,8 +139,7 @@ void atm_dev_deregister(struct atm_dev *
 
         warning_time = jiffies;
         while (atomic_read(&dev->refcnt) != 1) {
-                current->state = TASK_INTERRUPTIBLE;
-                schedule_timeout(HZ / 4);
+                msleep(250);
                 if ((jiffies - warning_time) > 10 * HZ) {
                         printk(KERN_EMERG "atm_dev_deregister: waiting for "
                                "dev %d to become free. Usage count = %d\n",
_