Hi,

Please consider applying.

Description: Use ssleep() instead of schedule_timeout() to guarantee the task
delays as expected. The current code uses TASK_INTERRUPTIBLE, but does not check
for signals / early return, so ssleep() should be appropriate. I am fairly
certain the time conversion is ok, as well.

Signed-off-by: Nishanth Aravamudan <nacc@us.ibm.com>
Signed-off-by: Domen Puncer <domen@coderock.org>
---


 kj-domen/sound/isa/sb/emu8000.c |    4 ++--
 1 files changed, 2 insertions(+), 2 deletions(-)

diff -puN sound/isa/sb/emu8000.c~ssleep-sound_isa_sb_emu8000 sound/isa/sb/emu8000.c
--- kj/sound/isa/sb/emu8000.c~ssleep-sound_isa_sb_emu8000	2005-01-23 00:24:32.000000000 +0100
+++ kj-domen/sound/isa/sb/emu8000.c	2005-01-23 00:24:33.000000000 +0100
@@ -25,6 +25,7 @@
 #include <linux/sched.h>
 #include <linux/slab.h>
 #include <linux/ioport.h>
+#include <linux/delay.h>
 #include <sound/core.h>
 #include <sound/emu8000.h>
 #include <sound/emu8000_reg.h>
@@ -355,8 +356,7 @@ init_arrays(emu8000_t *emu)
 {
 	send_array(emu, init1, ARRAY_SIZE(init1)/4);
 
-	set_current_state(TASK_INTERRUPTIBLE);
-	schedule_timeout((HZ * (44099 + 1024)) / 44100); /* wait for 1024 clocks */
+	ssleep(1);
 	send_array(emu, init2, ARRAY_SIZE(init2)/4);
 	send_array(emu, init3, ARRAY_SIZE(init3)/4);
 
_